php如何彈出提示框？php確認取消彈出框怎么設置？

php如何彈出提示框：

< ?PHP

echo "< script language=

\"JavaScript\">alert

(\"你好\");< /script>";

?>

//或者

< ?PHP

print "< script language=

\"JavaScript\">alert

(\"你好\");< /script>";

?>

php確認取消彈出框怎么設置：

public void isHan() { AlertDialog.Builder builder=new AlertDialog.Builder(this); builder.setTitle("小韓提示"); builder.setIcon(android.R.drawable.ic_dialog_info); builder.setPositiveButton("確定", new DialogInterface.OnClickListener(){ //點擊確定執行 @Override public void onClick(DialogInterface arg0, int arg1) { }}); builder.setNegativeButton("返回", new DialogInterface.OnClickListener(){ //點擊取消執行 @Override public void onClick(DialogInterface arg0, int arg1) { }}); AlertDialog b = builder.create(); b.show();//顯示對話框 }